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The Baudhayana-Pythagoras Theorem

Only at a right angle

Two sides meet at a corner. A square is built on each side. A third square is built on the side across from the corner. Open the corner wider than 90°. Do the first two squares still add up to the third?

Sides 6 and 8 meet at A. Corner A is 60°. Squares at A: 36 + 64 = 100. Across: 52.
Step 1 of 3
  1. Sides 6 and 8 meet at A. Corner A is 60°. Squares at A: 36 + 64 = 100. Across: 52.
  2. Open A to exactly 90°. Across: 100. The totals match.
  3. Open A to 120°. Across: 148. The square across is bigger.

No. They add up to the square across only at exactly 90°.

Rule: Take the two squares at a corner. Their total equals the square across only at exactly 90°. Below 90°, the two squares together are bigger. Above 90°, the one across is bigger.

At A, the squares total 36 + 64 = 100 each time. The square across is 52, then 100, then 148.

Drag the slider to open the corner.

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This track

  1. 0 Start here
  2. 1 Naming the sides
  3. 2 A square on every side
  4. 3 The two smaller squares together
  5. 4 Only at a right angle
  6. 5 Finding the long side
  7. 6 Finding a shorter side
  8. 7 Testing a triangle without a protractor
  9. 8 Where it is used
  10. 9 Corner to corner of a square
  11. 10 The long side as a decimal
  12. 11 One triple makes many
  13. 12 The hidden depth of a pond
  14. 13 Checkpoint: roots, triples and a pond
  15. 14 The big picture
  16. 15 Track quiz

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