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Lesson 15 of 17

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Most of these rewrites run both ways. You can multiply the brackets out. You can also write the result back as brackets.

Algebraic identities on one screen
IdeaRememberExample
Cutting down(a − b)² = a² − 2ab + b². The corner is taken away twice.side 7, strip 2: leftover 25
One from anothera² − b² = (a − b)(a + b). Gap times total.101² − 99² = 400
Three parts(a+b+c)² = a²+b²+c²+2ab+2bc+2ca. Nine pieces, not three.213² = 45369
A cube(a+b)³ = a³+3a²b+3ab²+b³. Two kinds of block come three at a time.2 and 1: 27 bricks
The pairAdd to the middle, multiply to the last.x²+9x+20 = (x+4)(x+5)
A number in frontThe pair multiplies to first times last.3x²+11x+6 = (x+3)(3x+2)
CancellingStrike out only a shared factor, never a term that is added on.(x²−9)/(x+3) = x−3, if x ≠ −3
Adding twoBuild one shared bottom, then add the tops.1/x + 1/(x+1) = (2x+1)/(x²+x)
Your own claimOne disagreement settles it. A few agreements do not.(a+b)²−(a−b)² = 4ab
Two lettersSquare each part. The middle is twice their product, with the sign between the parts.(8a+3b)² = 64a²+48ab+9b²
Two cubesx³ − y³ = (x − y)(x² + xy + y²). x³ + y³ = (x + y)(x² − xy + y²).5³ − 3³ = 2 × 49 = 98
Round numbersa² = (a + b)(a − b) + b². Choose b to make a factor round.47² = 50 × 44 + 9 = 2209

Now open Chapter 4 in your book. It is Exploring Algebraic Identities.