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Lesson 8 of 17

What may be cancelled

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9 min

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(x + 3)/3 becomes x by striking out the two 3s. Striking out means crossing out the same thing above and below. Is that allowed? Judge five strikings-out.

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(x² − 9) / (x + 3).
Step 1 of 6
  1. (x² − 9) / (x + 3).
  2. Factor the top: (x − 3)(x + 3) / (x + 3).
  3. (x + 3) multiplies the whole top. It cancels.
  4. Left with x − 3.
  5. Compare: (x + 3) / 3. The 3 is added to x, not a factor.
  6. It does not cancel.

The rule

No. In (x + 3)/3 the 3 on top is added to x. It is not a factor.

Strike out only a shared factor. A factor multiplies the whole top or the whole bottom. A term that is added on is not a factor.

Test the claim at x = 3. (x + 3)/3 gives 6/3 = 2. But x gives 3. The numbers differ, so the rewrite is wrong.

Four of the five strikings-out, checked at x = 3
Written asStruck outBeforeAfterFair?
(x + 3)/3 → xthe two 3s23no
(3x + 6)/3 → x + 2a 3 from every term55yes
(x² − 9)/(x + 3) → x − 3the bracket (x + 3)00yes
(x + 5)/(x + 7) → 5/7the two x terms4/55/7no

In (3x + 6)/3, every term on top has a 3. So the top is 3(x + 2). That 3 multiplies the whole top, so it may be struck out.

When the bracket is zero

A struck-out bracket must not be zero. At x = −3 the bottom of (x² − 9)/(x + 3) is 0. Then the fraction has no value. So x − 3 matches the fraction only where x + 3 is not zero.

Try the lab to finish this lesson.