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Lesson 5 of 15

A family with one difference

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8 min

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Add one carbon to a chain. Two more hydrogens follow.

One carbon, four hydrogens: CH₄, methane.
Step 1 of 4
  1. One carbon, four hydrogens: CH₄, methane.
  2. Two carbons, six hydrogens: C₂H₆, ethane.
  3. Three carbons, eight hydrogens: C₃H₈, propane.
  4. Four carbons, ten hydrogens: C₄H₁₀, butane.

Pick a family. Slide the carbon count. Watch the mass step.

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The rule

A homologous series is a row of compounds with the same group. Each is one CH₂ above the last. They share chemical properties. Physical properties change step by step.

Take carbon's mass as 12 and hydrogen's as 1. So each CH₂ step adds 12 + 1 + 1 = 14 to the mass.

The alkane family, rung by rung
CarbonsFormulaMass
1CH₄16
2C₂H₆30
3C₃H₈44
4C₄H₁₀58

Chains with only single bonds have no group. They form a series too. Let n be the number of carbons. A saturated chain with no ring is CₙH₂ₙ₊₂. This family is the alkanes. A chain with one double bond is CₙH₂ₙ. These are the alkenes. One triple bond gives CₙH₂ₙ₋₂, the alkynes. For n = 2, they are ethane C₂H₆, ethene C₂H₄ and ethyne C₂H₂.

Replace one hydrogen of each alkane with –OH. You get the alcohols. Methanol is CH₃OH. Ethanol is C₂H₅OH. They differ by CH₂ too.

Melting and boiling points rise as the chain grows.

Watch out!

One CH₂ apart is not enough. Methanol, CH₃OH, and dimethyl ether, CH₃OCH₃, differ by CH₂. Their groups differ, so they are not one series.

Try the lab to finish this lesson.