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Lesson 9 of 14

Squared, then added

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9 min

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A 5 m ladder reaches 4 m up a wall. Its foot is 3 m out. Call the angle at the foot A. Square sin A and cos A. Add them.

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A right triangle with sides a, b, c. Side c is the hypotenuse.
Step 1 of 4
  1. A right triangle with sides a, b, c. Side c is the hypotenuse.
  2. a² + b² = c², by Pythagoras.
  3. Divide every term by c².
  4. That gives sin²A + cos²A = 1.

The proof in three moves

Write sin A as opposite ÷ hypotenuse. Write cos A as adjacent ÷ hypotenuse. Square each one:

sin²A = opposite² ÷ hypotenuse²

cos²A = adjacent² ÷ hypotenuse²

The two bottoms match. So add the tops over that bottom:

sin²A + cos²A = (opposite² + adjacent²) ÷ hypotenuse²

Pythagoras says opposite² + adjacent² = hypotenuse². So the fraction is hypotenuse² ÷ hypotenuse², which is 1.

Rule: sin²A + cos²A = 1 for every acute angle A.

Such an equation, true for every acute angle, is an identity.

For the ladder, sin A = 4/5 and cos A = 3/5. The squares are 16/25 and 9/25. Their sum is 25/25 = 1.

Watch out!

Sin²A means (sin A)². Sin²A is not sin(A²). And sin A + cos A is not 1. For the ladder, sin A + cos A is 7/5.

Try the lab to finish this lesson.